x^2-3.25x+1.08614232209=0

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Solution for x^2-3.25x+1.08614232209=0 equation:



x^2-3.25x+1.08614232209=0
a = 1; b = -3.25; c = +1.08614232209;
Δ = b2-4ac
Δ = -3.252-4·1·1.08614232209
Δ = 6.21793071164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.25)-\sqrt{6.21793071164}}{2*1}=\frac{3.25-\sqrt{6.21793071164}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.25)+\sqrt{6.21793071164}}{2*1}=\frac{3.25+\sqrt{6.21793071164}}{2} $

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